Find the next three terms of the following sequences:
(i) 8, 24, 72, ...
(ii) 5, 1, -3, ...
(iii) 1/4, 2/9, 3/16, ...
Let's examine the pattern:
8 Ć 3 = 24
24 Ć 3 = 72
This is a geometric sequence where each term is multiplied by 3.
Next terms: 72 Ć 3 = 216
216 Ć 3 = 648
648 Ć 3 = 1,944
Let's look at the differences:
1 - 5 = -4
-3 - 1 = -4
This is an arithmetic sequence with common difference -4.
Next terms: -3 + (-4) = -7
-7 + (-4) = -11
-11 + (-4) = -15
Let's analyze the pattern:
Numerators: 1, 2, 3,... (increasing by 1)
Denominators: 4, 9, 16,... (perfect squares: 2², 3², 4²)
So the nth term is n/(n+1)²
Next terms:
4/5² = 4/25
5/6² = 5/36
6/7² = 6/49
Find the first four terms of the sequences whose nth terms are given by:
(i) aā = 3n - 2
(ii) aā = (-1)n+1 n(n+1)
(iii) aā = 2n² - 6
Let's find terms for n = 1, 2, 3, 4:
aā = 3(1) - 2 = 1
aā = 3(2) - 2 = 4
aā = 3(3) - 2 = 7
aā = 3(4) - 2 = 10
Sequence: 1, 4, 7, 10,...
Let's calculate each term:
aā = (-1)2 Ć 1 Ć 2 = 1 Ć 2 = 2
aā = (-1)3 Ć 2 Ć 3 = -1 Ć 6 = -6
aā = (-1)4 Ć 3 Ć 4 = 1 Ć 12 = 12
aā = (-1)5 Ć 4 Ć 5 = -1 Ć 20 = -20
Sequence: 2, -6, 12, -20,...
Calculating each term:
aā = 2(1)² - 6 = 2 - 6 = -4
aā = 2(2)² - 6 = 8 - 6 = 2
aā = 2(3)² - 6 = 18 - 6 = 12
aā = 2(4)² - 6 = 32 - 6 = 26
Sequence: -4, 2, 12, 26,...
Find the nth term of the following sequences:
(i) 2, 5, 10, 17,...
(ii) 0, 1/2, 2/3, 3/4,...
(iii) 3, 8, 13, 18,...
Let's examine the pattern:
2 = 1² + 1
5 = 2² + 1
10 = 3² + 1
17 = 4² + 1
This suggests aā = n² + 1
Let's verify:
aā = 5² + 1 = 26 (next term would be 26)
So nth term: aā = n² + 1
Looking at numerators and denominators:
Numerators: 0, 1, 2, 3,... (n-1)
Denominators: 1, 2, 3, 4,... (n)
So nth term: aā = (n-1)/n
Let's verify:
aā = (5-1)/5 = 4/5 (next term would be 4/5)
This is an arithmetic sequence:
First term (aā) = 3
Common difference (d) = 8 - 3 = 5
General form: aā = aā + (n-1)d
So nth term: aā = 3 + (n-1)Ć5 = 5n - 2
Let's verify:
aā = 5Ć5 - 2 = 23 (next term would be 23)
Find the indicated terms of the sequences whose nth terms are given by:
(i) aā = 5n/(n+2); find aā and aāā
(ii) aā = 2n - n; find aā and aāā
Calculating aā:
aā = 5Ć6 / (6+2) = 30/8 = 15/4
Calculating aāā:
aāā = 5Ć13 / (13+2) = 65/15 = 13/3
Calculating aā:
aā = 2ā“ - 4 = 16 - 4 = 12
Calculating aāā:
aāā = 2¹¹ - 11 = 2048 - 11 = 2037
Find aā and aāā whose nth term is:
aā = { (n²-2)/n if n is even
aā = (2n+1)/3 if n is odd }
Using the even formula: aā = (n²-2)/n
aā = (8² - 2)/8 = (64 - 2)/8 = 62/8 = 31/4
Using the odd formula: aā = (2n+1)/3
aāā = (2Ć15 + 1)/3 = (30 + 1)/3 = 31/3 = 31/3
If aā = 1, aā = 1 and aā = aāāā + aāāā for n ā„ 3, then find the first six terms.
aā = 1
aā = 1
aā = aā + aā = 1 + 1 = 2
aā = aā + aā = 1 + 2 = 3
aā = aā + aā = 2 + 3 = 5
aā = aā + aā = 3 + 5 = 8
1, 1, 2, 3, 5, 8
This is the famous Fibonacci sequence!